SolutionHard
Question
Mole fraction of C3H5(OH)3 in a solution of 36 g of water and 46 g of glycerine is :
Options
A.0.46
B.0.36
C.0.20
D.0.40
Solution
Mole of H2O = 
= 2
Mole of glycerine =
= 0.5
total mole = 2 + 0.5 = 2.5
Mole fractions of glycerine =
X0 = 0.2 Ans.
= 2Mole of glycerine =
= 0.5total mole = 2 + 0.5 = 2.5
Mole fractions of glycerine =
X0 = 0.2 Ans.
Create a free account to view solution
View Solution FreeMore Solution Questions
A solution containing 30 g of a non-volatile solute exactly in 90 g water has a vapour pressure of 2.8 kPa at 298 K. On ...To 10 mL of 1 M BaCl2 solution 5 mL of 0.5 M K2SO4 is added. BaSO4 is precipitated out. What will happen ?...Which of the following is correct for an ideal solution ?...A 5% solution (by mass) of cane sugar in water has freezing point of 271 K and freezing point of pure water is 273.15 K....Assuming each salt to be 90% dissociated which of the following will have highest osmotic pressure ?...