SolutionHard
Question
Mole fraction of C3H5(OH)3 in a solution of 36 g of water and 46 g of glycerine is :
Options
A.0.46
B.0.36
C.0.20
D.0.40
Solution
Mole of H2O = 
= 2
Mole of glycerine =
= 0.5
total mole = 2 + 0.5 = 2.5
Mole fractions of glycerine =
X0 = 0.2 Ans.
= 2Mole of glycerine =
= 0.5total mole = 2 + 0.5 = 2.5
Mole fractions of glycerine =
X0 = 0.2 Ans.
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