SolutionHard
Question
Mole fraction of a non-electrolyte in aqueous solution is 0.07. If Kf is 1.86o mol-1 kg, depression in f.p., ᐃTf, is:
Options
A.0.26o
B.1.86o
C.0.13o
D.7.78o
Solution
Firstly we have to convert mole fraction into molality.
Molality =
= 4.18
Now, ᐃTf = kf m
= 1.86 × 4.18 = 7.780 .
Molality =
= 4.18Now, ᐃTf = kf m
= 1.86 × 4.18 = 7.780 .
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