SolutionHard
Question
20 g of a substance were dissolved in 500 mL of water and the osmotic pressure of the solution was found to be 600 mm of mercury at 15oC. The molucular weight of substance is :
Options
A.998
B.1028
C.1098
D.1198
Solution
πV = nRT
× 0.082 ×(273 + 15)
× 0.082 × 288
m =
= 1198
× 0.082 ×(273 + 15)× 0.082 × 288m =
= 1198Create a free account to view solution
View Solution FreeMore Solution Questions
A 20.0 mL sample of CuSO4 solution was evaporated to dryness, leaving 0.967 g of residue. What was the molarity of the o...Under the condition of similar temperature, which of the following solution will have minimum vapour pressure?...Two beakers, one containing 20 ml of a 0.05 M aqueous solution of a non volatile, non electrolyte and the other, the sam...A certain compound (X) is used in laboratory for analysis, its aqueous solution gives brown appearanceon addition copper...Two elements A and B form compounds having molecular formulae AB2 and AB4. When dissolved in 20.0 g of Benzene, 1.00 g o...