SolutionEasy
Question
20 g of a substance were dissolved in 500 mL of water and the osmotic pressure of the solution was found to be 600 mm of mercury at 15oC. The molucular weight of substance is :
Options
A.998
B.1028
C.1098
D.1198
Solution
πV = nRT
× 0.082 ×(273 + 15)
× 0.082 × 288
m =
= 1198
× 0.082 ×(273 + 15)× 0.082 × 288m =
= 1198Create a free account to view solution
View Solution FreeMore Solution Questions
If 100 mL of 1 M H2SO4 solution is mixed with 100 mL of 98% (W/W) of H2SO4 solution (d = 0.1 g mL), then...Based on the given diagram, which of the following statements regarding the solutions of two miscible volatile liquids a...5 g of urea is dissolved in one kg of water. Up to what temperature, the solution may be cooled before ice starts crysta...After removing the hard shell of an egg by dissolving in dilute HCl, a semipermeable membrane can be visible. If such an...A semipermeable membrane separates a solution which is 0.012 M in glucose from one that is 0.250 M in glucose. On which ...