Coordination CompoundHard
Question
How many isomers are possible for the complex ion [Cr(NH3)Cl3(OH)2]2- ?
Options
A.2
B.3
C.4
D.5
Solution
It is Ma3b2c type. So it has three isomer which are as follow :
(aa)(ab)(bc) (optically inactive)
(aa)(bb)(ac) (optically inactive)
(ab)(ab)(ac) (optically inactive)
(aa)(ab)(bc) (optically inactive)
(aa)(bb)(ac) (optically inactive)
(ab)(ab)(ac) (optically inactive)
Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
The total no. of possible isomers of the compound [CuII(NH3)4][PtIICl4] are :-...Consider the following reaction and statements : [Co(NH3)4Br2]+ + Br- → [Co(NH3)3Br3] + NH3 (I) Two isomers are produ...For the reaction, Ni2+ + 4NH3 ⇋ [Ni(NH3)4]2+ at equilibrium, if the solution contains 1.6 ×10-4% of nickel in...Which of the following forms with an excess of CN–, a complex having coordination number two?...The ligand called π acid is :...