Coordination CompoundHard
Question
Wilkinson′s catalyst react with H2 to form an octahedral complex in which Rh (Z = 45) has the following electronic configuration in the ligand field, t2g2,2,2, eg0,0
Then which of the following is correct about this new complex ?
Then which of the following is correct about this new complex ?
Options
A.It is diamagnetic
B.Its IUPAC name is chloridotris(triphenylphosphine)rhodium(I)
C.Hybridisation of Rh (I) is sp3d2
D.It is a paramagnetic complex
Solution
All electrons are paired ; so diamagnetic and has d2sp3 hybridisation.
[RhCl(PPh3)3] + H2 [RhCl(H)2(PPh3)3]
Wilkinsons′s catalyst
New complex chloridodihydridotris(triphenyl phosphine)rhodium(III)
Rh(III) → 4d6
[RhCl(PPh3)3] + H2 [RhCl(H)2(PPh3)3]
Wilkinsons′s catalyst
New complex chloridodihydridotris(triphenyl phosphine)rhodium(III)
Rh(III) → 4d6
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