Analytical ChemistryHard
Question
Cu2+ ions give white precipitate with :
Options
A.potassium iodide solution.
B.potassium thiocyanate and saturated solution of SO2.
C.excess potassium cyanide solution.
D.potassium hydroxide solution.
Solution
(A) 2Cu2+ + 4I- → Cu2I2 (white) ↓ + I2.
(B) 2Cu2+ + 4SCN- + SO2 + 2H2O → 2CuSCN ↓ (white) + 2SCN- + SO42- + 4H+.
(C) Cu2+ + 6CN- → [Cu(CN)4]3- (soluble complex) + (CN)2.
(D) Cu2+ + 2OH- → Cu(OH)2↓ (blue).
(B) 2Cu2+ + 4SCN- + SO2 + 2H2O → 2CuSCN ↓ (white) + 2SCN- + SO42- + 4H+.
(C) Cu2+ + 6CN- → [Cu(CN)4]3- (soluble complex) + (CN)2.
(D) Cu2+ + 2OH- → Cu(OH)2↓ (blue).
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