Analytical ChemistryHard
Question
Consider the following statements,
S1 : precipitate of lead thiosulphate is soluble in excess sodium thiosulphate (Na2S2O3).
S2 : moderately concentrated solution of Ba2+ ions gives white precipitate of BaS2O3 with hypo.
S3 : white precipitate of CaSO3 dissolves when excess of SO2 gas is passed through it.
S4 : Hg2+ + S2O32- + H2O → HgS↓ + SO42- + 2H+
and arrange in the order of true / false.
S1 : precipitate of lead thiosulphate is soluble in excess sodium thiosulphate (Na2S2O3).
S2 : moderately concentrated solution of Ba2+ ions gives white precipitate of BaS2O3 with hypo.
S3 : white precipitate of CaSO3 dissolves when excess of SO2 gas is passed through it.
S4 : Hg2+ + S2O32- + H2O → HgS↓ + SO42- + 2H+
and arrange in the order of true / false.
Options
A.T F T T
B.T T F F
C.T T T T
D.T F T F
Solution
S1 : PbS2O3↓ + 2S2O32- → [Pb(S2O3)2]2- (soluble complex).
S2 : Ba2+ + S2O32- → BaS2O3 ↓ (white).
S3 : CaSO3 + H2O + SO2 → Ca(HSO3)2.
S4 : Correct reaction, Hg2+ + S2O32- + H2O → HgS↓ + SO42- + 2H+.
S2 : Ba2+ + S2O32- → BaS2O3 ↓ (white).
S3 : CaSO3 + H2O + SO2 → Ca(HSO3)2.
S4 : Correct reaction, Hg2+ + S2O32- + H2O → HgS↓ + SO42- + 2H+.
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