Analytical ChemistryHard
Question
Consider the following observation :
Mn+ + HCl (dilute) → white precipitate
water soluble
yellow precipitate.
The metal ion Mn+ will be :
Mn+ + HCl (dilute) → white precipitate
The metal ion Mn+ will be :
Options
A.Hg2+
B. Ag+
C.Pb2+
D.Sn2+
Solution
Pb2+ + 2Cl- → PbCl2 ↓ (soluble in hot water) ; PbCl2 + CrO42- → PbCrO4 ↓ (yellow) + 2Cl-.
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