Ionic EquilibriumHard
Question
The best explanation for the solubility of MnS in dilute HCl is that :
Options
A.Solubility product of MnCl2 is less than that of MnS
B.Concentration of Mn2+ is lowered by the formation of complex ions with chloride ions
C.Concentration of sulphide ions is lowered by oxidation to free sulphur
D.Concentration of sulphide ions is lowered by formation of weak acid H2S
Solution
MnS(s) ⇋ Mn2+ (aq) + S2- (aq) ;
S2- (aq) + 2H+ (aq) H2S (aq)
S2- (aq) + 2H+ (aq) H2S (aq)
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
0.1mol HCl is dissolved in distilled water of volume V then at limV→∞ (pH)solution is equal to...In the manufacture of NH3 in Haber′s continuous flow process involving the reaction H2(g) + 3H2(g) 2NH3(g) ᐃ...The solubility products of MA, MB, MB and MD are 1.8 × 10-10, 4 × 10-3, 4 × 10-8 and 6 × 10-5 respec...On adding 0.1 M solution each of [Ag+], [Ba2+], [Ca2+] in a Na2So4 solution, species first precipited is...Approximate pH of 0.1 M aqueous H2S solution when K1 and K2 for H2S at 25oC are 1 × 10-7 and 1.3 × 10-13 respe...