Ionic EquilibriumHard

Question

The [OH-] in 100.0 ml of 0.016 M-HCl (aq) is :

Options

A.5 × 1012 M
B.3 × 10-10 M
C.6.25 × 10-13 M
D.2.0 × 10-9 M.

Solution

[H+] = 0.016 M
[H+] [OH-] = 10-14  ⇒ [OH-] = = 6.25 × 10-13 M

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