Ionic EquilibriumHard
Question
The [OH-] in 100.0 ml of 0.016 M-HCl (aq) is :
Options
A.5 × 1012 M
B.3 × 10-10 M
C.6.25 × 10-13 M
D.2.0 × 10-9 M.
Solution
[H+] = 0.016 M
[H+] [OH-] = 10-14 ⇒ [OH-] =
= 6.25 × 10-13 M
[H+] [OH-] = 10-14 ⇒ [OH-] =
= 6.25 × 10-13 MCreate a free account to view solution
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