Ionic EquilibriumHard
Question
A definite volume of a N/20 CH3COOH (pKa = 4.7447) is titrated with a strong base (NaOH). It is found that 80 equal sized drops of NaOH, added from a burette effect the complete neutralisation. Find the pH, when the acid solution is neutralised to the extent of 20%.
Options
A.4.14
B.9.86
C.5.34
D.8.68
Solution
WA(CH3COOH) is titrated with SB(NaOH) and 20% of the WA is neutralised, so 20% of the salt of WA/SB (CH3COOH) is formed and 80% of the WA(CH3COOH) is left. So an acidic buffer is formed.
∴ [Acid] = 80; [Salt] = 20
pH = pKa + log
= 4.7447 + log
= 4.7447 + log
= 4.7447 - 2 log 2 = 4.7447 - 2 × 0.3010 = 4.14
∴ [Acid] = 80; [Salt] = 20
pH = pKa + log
= 4.7447 + log
= 4.7447 + log
= 4.7447 - 2 log 2 = 4.7447 - 2 × 0.3010 = 4.14
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
In the manufacture of NH3 in Haber′s continuous flow process involving the reaction H2(g) + 3H2(g) 2NH3(g) ᐃ...At infinite dilution the percentage dissociation of both weak acid and weak base is:...pH for the solution of salt undergoing anionic hydrolysis (say CH3COONa) is given by:...The pH of a solution obtained by mixing 100 ml of 0.2 M CH3COOH with 100 ml of 0.2 M NaOH would be : (pKa for CH3COOH = ...Auto-ionisation of liquid NH3 is 2NH3 ⇋NH4+ + NH2-with KNH3 = [NH4+] [NH2-] = 10-30 at -50oCNumber of amide ions (...