SHMHard
Question
A man of mass 60 kg standing on a platform executing S.H.M. in the vertical plane. The displacement from the mean position varies as y = 0.5 sin (2πft). The minimum value of f, for which the the man will feel weightlessness at the highest point is : (y is in metres)
Options
A.
B.4πg
C.
D.2π√2g
Solution
For weightlessness
mg = mω2a ⇒ g = (2πf)2(0.5)
⇒2πf = √2 g ⇒ f =
mg = mω2a ⇒ g = (2πf)2(0.5)
⇒2πf = √2 g ⇒ f =
Create a free account to view solution
View Solution FreeMore SHM Questions
The spring constant of a spring is K. When it is divided into n equal parts, then what is the spring constant of one pie...As shown in the figure, a spring is kept in a stretched position with some extension by holding the masses 1 kg and 0.2 ...The mass of particle executing S.H.M. is 1 gm. If its periodic time is π seconds, the value of force constant is :...A particle is acted upon by force F = F cos(ωt) along X-axis. The amplitude of its velocity is given by v = . Choos...According to a scientists, he applied a force F= − cx1/3 on a particle and the particle is performing SHM. No othe...