SHMMedium
Question
A man of mass 60 kg standing on a platform executing S.H.M. in the vertical plane. The displacement from the mean position varies as y = 0.5 sin (2πft). The minimum value of f, for which the the man will feel weightlessness at the highest point is : (y is in metres)
Options
A.
B.4πg
C.
D.2π√2g
Solution
For weightlessness
mg = mω2a ⇒ g = (2πf)2(0.5)
⇒2πf = √2 g ⇒ f =
mg = mω2a ⇒ g = (2πf)2(0.5)
⇒2πf = √2 g ⇒ f =
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