SHMMedium
Question
A test tube of length l and area of cross-section A has some iron fillings of mass M as shown in figure. The test tube floats normally in a liquid of density ρ with length x dipped in the liquid. A disturbing force makes the tube oscillate in the liquid. The time period of oscillation is given by -
Options
A.
B.
C.
D.
Solution
at equilibrium position
Axρg = Mg M = Axρ ----------(1)
If tube displaced by distance y vertically downward then net force on tube
A(x + y)ρg − Mg = Ma
a =
y ⇒ a = (g/x)y
Time period T = 2π
Axρg = Mg M = Axρ ----------(1)
If tube displaced by distance y vertically downward then net force on tube
A(x + y)ρg − Mg = Ma
a =
y ⇒ a = (g/x)yTime period T = 2π
Create a free account to view solution
View Solution FreeMore SHM Questions
The displacement of a particle along the x axis is given by x = a sin2 ωt . The motion of the particle corresponds ...A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for a...Values of the acceleration of a particle moving in simple harmonic motion as a function of its displacement x are given ...An elastic string of length l supports a heavy particle of mass m and the system is in equilibrium with elongation produ...Mass ′m′ is suspended from a spring of force constant K. Spring is cut into two equal parts and same mass is...