SHMHard
Question
The period of small oscillations of a simple pendulum of length l if its point of suspension O moves a with a constant acceleration α = α1 î − α2 ĵ with respect to earth is
Options
A.
B.
C.
D.
Solution
Point O is moving as shown

So acc. Of particle w.r.t O
= (−αî + (α2 − g)ĵ )
So geff. =
So time period
= 2π

So acc. Of particle w.r.t O
= (−αî + (α2 − g)ĵ )
So geff. =
So time period
= 2π
Create a free account to view solution
View Solution FreeMore SHM Questions
For a particle executing simple harmonic motion, the acceleration is proportional to...Benzene and naphthalene form an ideal solution at room temperature. For this process, the true statement(s)is(are)...A simple pendulum is suspended from the ceiling of a vehicle, its time period is T. Vehicle is moving with constant velo...A point particle of mass 0.1 kg is executing SHM of amplitude 0.1 m When the particle passes through the means position,...A pendulum with time period of 1s is losing energy due to damping. At certain time its energy is 45 J. If after completi...