NEET | 2017SHMEasy
Question
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is :-
Options
A.
B.
C.
D.
Solution
Amplitude A = 3 cm
When particle is at x = 2 cm ,
its |velocity| = |acceleration|
i.e.,
T =
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