Chemical Kinetics and Nuclear ChemistryHard
Question
T50 (Half-life period) of first-order reaction is 10 minute. Starting with 10 mol L-1, rate after 20 minute is :
Options
A.0.0693 mol L-1 min-1
B.0.0693 × 2.5 mol L-1 min-1
C.0.0693 × 5 mol L-1 min-1
D.0.0693 × 10 mol L-1 min-1
Solution
Conc. after at 2 half life (20 minute) = 
× (Initial conc.)
=
× 10 = 2.5 M.
Then Rate = k[at] =
× 2.5 = .06932 × 2.5
× (Initial conc.)=
× 10 = 2.5 M.Then Rate = k[at] =
× 2.5 = .06932 × 2.5Create a free account to view solution
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