Chemical Kinetics and Nuclear ChemistryHard
Question
For a given reaction A → Product, rate is 1 × 10-4 M s-1 when [A] = 0.01 M and rate is 1.41 × 10-4 M s-1 when [A] = 0.02 M. Hence, rate law is :
Options
A.
= k [A]2
= k [A]2B.= k [A]
= k [A]C.
[A]
[A]D.
= k[A]1/2
= k[A]1/2Solution
A → Product
We know, Rate = K [conc.]n
1 √ 10-4 = K [.01]n .....(i)
1.41 × 10-4 = K [.02]n .....(ii)
(i) / (ii)
n =
Then
= K [A]1/2
We know, Rate = K [conc.]n
1 √ 10-4 = K [.01]n .....(i)
1.41 × 10-4 = K [.02]n .....(ii)
(i) / (ii)
n =
Then
= K [A]1/2Create a free account to view solution
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