Chemical Kinetics and Nuclear ChemistryHard
Question
The rate law for a reaction between the substances A and B is given by rate = K[A]n [B]m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as :
Options
A.1/2m + n
B.(m + n)
C.(n - m)
D.2(n - m)
Solution
Rate = K[A]n [B]m
Given, doubling the concentration of A and halving the concentration of B
then Rate2 = K[2A]n [
]m
Rate2 = K[A]n [B]mx 2(n-m)
Given, doubling the concentration of A and halving the concentration of B
then Rate2 = K[2A]n [
]mRate2 = K[A]n [B]mx 2(n-m)
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