ElectrochemistryHard
Question
What is cell entropy change of the following cell ?
Pt(s) | H2 (g) | CH3COOH, HCl || KCl (aq) | Hg2Cl2 (s) | Hg
P = 1 atm 0.1M 0.1M
Emf of the cell is found to be 0.045 V at 298 K and temperature coefficient is 3.4 × 10-4 V K-1
Given Ka(CH3COOH) = 10-5 M
Pt(s) | H2 (g) | CH3COOH, HCl || KCl (aq) | Hg2Cl2 (s) | Hg
P = 1 atm 0.1M 0.1M
Emf of the cell is found to be 0.045 V at 298 K and temperature coefficient is 3.4 × 10-4 V K-1
Given Ka(CH3COOH) = 10-5 M
Options
A.60
B.65.2
C.69.2
D.63.5
Solution
Considering the cell reaction
H2 + 2e → 2H+
Hg22+ + 2e → 2Hg (l) + 2Cl- (aq)
ᐃS = nF
= 2 × 96500 × 3.4 × 10-4 = 65.223 J/K/mole
H2 + 2e → 2H+
Hg22+ + 2e → 2Hg (l) + 2Cl- (aq)
ᐃS = nF
= 2 × 96500 × 3.4 × 10-4 = 65.223 J/K/moleCreate a free account to view solution
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