ElectrochemistryHard
Question
During the electrolysis of 0.1 M CuSO4 solution using copper electrodes, a depletion of [Cu++] occurs near the cathode with a corresponding excess near the anode, owing to inefficient stirring of the solution. If the local concentrations of [Cu++] near the anode & cathode are respectively 0.12 M & 0.08 M, calculate the back e.m.f. developed. Temperature = 298 K .
Options
A.22 mV
B.5.2 mV
C.29 mV
D.59 mV
Solution
Ecell = Eocell -
log10 
Eocell = 0
Ecell = -
log10
= + 5.2 mV.
Eocell = 0
Ecell = -
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Consider the following cell reaction:2Fe(s) + O2(g) + 4H+(aq) → 2Fe2+(aq) + 2H2O(l) Eo = 1.67V At [Fe2+] = 10-3 M,...The standard reduction potential at 25°C of the reaction 2H2O + 2e− $\rightleftharpoons$H2 + 2OH− is −0.84 V. Calculate ...Zn + Cu2+(aq) ⇋ Cu + Zn2+(aq)Reaction quotient is Q = . Variation of Ecell with log Q is of the type with OA = 1.1...The reaction, H2(g) + AgCl(s) → H+ (aq) + Cl- (aq) + Ag(s) occurs in the galvanic cell :...The chemical reaction2AgCl(s) + H2 (g) → 2HCl (aq) + 2Ag (s)taking place in a galvanic cell is represented by the ...