ElectrochemistryHard
Question
Pure water is saturated with pure solid AgCl, a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 25oC. This experiment is then repeated with a saturated solution of AgI. If the difference in potential in the two cases is 0.177V. What is the ratio of solubilty product (solubilty) of AgCl and AgI at the temperature of the experiment ?
Options
A.103
B.106
C.102
D.102
Solution
Ag → Ag+ + e-
E1 = Eoxid + Ecalomel
= E′ -
log + Ecalomel
E2 = E′ -
log + Ecalomel
E2 - E1 = 0.177 = 0.0591 log
= 103.
E1 = Eoxid + Ecalomel
= E′ -
log + EcalomelE2 = E′ -
log + EcalomelE2 - E1 = 0.177 = 0.0591 log
= 103.Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
What is the emf at 25oC for the cell, Ag Pt The standard reduction potentials for the half-reactions AgBr + e- → A...Consider the following statements:(I) is more stable than (II) is more stable than (III) is more stable than (IV) is mor...Conductance measurements can be used to detect the end point of acid-base titrations. Which of the following plots corre...Which of the following has longest C - O bond :...In which of the following molecules π - electron density in ring is maximum :...