ElectrochemistryHard
Question
Pure water is saturated with pure solid AgCl, a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 25oC. This experiment is then repeated with a saturated solution of AgI. If the difference in potential in the two cases is 0.177V. What is the ratio of solubilty product (solubilty) of AgCl and AgI at the temperature of the experiment ?
Options
A.103
B.106
C.102
D.102
Solution
Ag → Ag+ + e-
E1 = Eoxid + Ecalomel
= E′ -
log + Ecalomel
E2 = E′ -
log + Ecalomel
E2 - E1 = 0.177 = 0.0591 log
= 103.
E1 = Eoxid + Ecalomel
= E′ -
log + EcalomelE2 = E′ -
log + EcalomelE2 - E1 = 0.177 = 0.0591 log
= 103.Create a free account to view solution
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