ElectrochemistryHard
Question
At 25°C, the solubility product of CuCl is 2.0 × 10−7 and $E_{Cl^{-}|CuCl|Cu}^{o}$ is 0.128 V. The value of $E_{Cu^{+}|Cu}^{o}$ is (log 2 = 0.3; 2.303 RT/F = 0.06)
Options
A.+1.08 V
B.+0.53 V
C.+1.682 V
D.+0.878 V
Solution
$E_{Cl^{-}|CuCl|Cu}^{o} = E_{Cu^{+}|Cu}^{o} - \frac{0.06}{1}\log\frac{1}{K_{sp}}$
$\text{Or, 1.28 = }E_{Cu^{+}|Cu}^{o} - \frac{0.06}{1}.\log\frac{1}{2 \times 10^{- 7}} $$$\Rightarrow E_{Cu^{+}|Cu}^{o} = 1.682\text{ V}$$
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