ElectrochemistryHard

Question

Electrolysis of a solution of MnSO4 in aqueous sulphuric acid is a method for the preparation of MnO2 as per the reaction: Mn2+ (aq) + 2H2O → MnO2(s) + 2H+ (aq) + H2(g).

Passing a current of 19.3 A for 2 h gives only 52.2 g of MnO2. The current efficiency is (Mn = 55)

Options

A.8.33%
B.83.33%
C.41.67%
D.100%

Solution

$\frac{w}{E} = \frac{Q}{F} \Rightarrow \frac{52.2}{87} \times 2 = \frac{19.3 \times 2 \times 3600 \times \eta}{96500} \Rightarrow \eta = 0.8333\text{ or 83.33\%}$

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