ElectrochemistryHard
Question
The standard reduction potentials E° of the following systems are
System E° (volts)
(i) MnO4- + 8H+ + 5e- → Mn2+ + 4H2O 1.51
(ii) Sn4+ + 2e- → Sn2+ 0.15
(iii) Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O .33
(iv) Ce4+ + e- → Ce3+ 1.61
The oxidising power of the various species decreases in the order
System E° (volts)
(i) MnO4- + 8H+ + 5e- → Mn2+ + 4H2O 1.51
(ii) Sn4+ + 2e- → Sn2+ 0.15
(iii) Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O .33
(iv) Ce4+ + e- → Ce3+ 1.61
The oxidising power of the various species decreases in the order
Options
A.Ce4+ > Cr2 O72- > Sn4+ > MnO4-
B.Ce4+ > MnO4- > Cr2 O72- > Sn4+
C.Cr2O72- > Sn4+ > Ce4+ > MnO4-
D.MnO4- > Ce4+ > Sn4+ > Cr2 O72-
Solution
Higher the std. reduction potential, higher is the oxidising power.
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