ElectrochemistryMedium
Question
The ECell for Ag(s)|AgI (satd)||Ag+ (0.10 M)|Ag (s) is +0.413 V. What is the value of Ksp of AgI?
Options
A.1.0 × 10−8
B.1.0 × 10−7
C.1.0 × 10−14
D.1.0 × 10−16
Solution
$\text{L.E}:Ag(s) \rightleftharpoons Ag^{+}\left( C_{1} = \sqrt{K_{sp}}M \right) + e^{-}$
$\text{R.E}:Ag^{+}\left( C_{2} = 0.1M \right) + e^{-} \rightleftharpoons Ag(s) $$${\therefore\text{Net reaction: }Ag^{+}\left( C_{2} \right) \rightleftharpoons Ag^{+}\left( C_{1} \right) }{E_{cell} = - \frac{0.059}{1}.\log\frac{C_{1}}{C_{2}} \Rightarrow 0.413 = - \frac{0.059}{1}.\log\frac{\sqrt{K_{sp}}}{0.1} }{\therefore K_{sp} = 1.0 \times 10^{- 16}}$$
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