ElectrochemistryHard
Question
On electrolysis, in which of the following, O2 would be liberated at the anode ?
Options
A.dilute H2SO4 with Pt electrodes
B.aqueous AgNO3 solution with Pt electrodes
C.dilute H2SO4 with Cu electrodes
D.aqueous NaOH with a Fe cathode & a Pt anode
Solution
(A) Anode 2H2O → O2 + 4H+ + 4e-
(B) Anode 2H2O → O2 + 4H+ + 4e-
(C) Anode Cu → Cu2+ + 2e-
(D) Anode 2H2O → O2 + 4H+ + 4e-
(B) Anode 2H2O → O2 + 4H+ + 4e-
(C) Anode Cu → Cu2+ + 2e-
(D) Anode 2H2O → O2 + 4H+ + 4e-
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