ElectrochemistryMedium

Question

The distance between two electrodes of a cell is 2.5 cm and area of each electrode is 5 cm2. The cell constant is

Options

A.0.5 m−1
B.12.5 cm3
C.2.0 cm
D.50 m−1

Solution

Cell constant, $C = \frac{l}{A} = \frac{2.5}{5} = 0.5\text{ c}\text{m}^{- 1} = 50\text{ }\text{m}^{- 1}$

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