ElectrochemistryHard
Question
The Eo in the given figure is,
Options
A.0.5
B.0.6
C.0.7
D.0.8
Solution
ClO3- + 2H2O + 4e → ClO- + 4OH- ; ᐃG1o
ClO- + H2O + e →
Cl2 + 2OH- ; ᐃG2o
Cl2 + e → Cl- ; ᐃG3o
__________________________________
ClO3- + 3H2O + 3e → Cl- + 6OH- ; ᐃGo
__________________________________
∴ ᐃGo = ᐃG1o + ᐃG2o + ᐃG3o
- 6FEo = - 4F × 0.54 - 1F × 0.45 - 1F × 1.07
Eo = +
= + 0.61 V
ClO- + H2O + e →
Cl2 + 2OH- ; ᐃG2oCl2 + e → Cl- ; ᐃG3o__________________________________
ClO3- + 3H2O + 3e → Cl- + 6OH- ; ᐃGo
__________________________________
∴ ᐃGo = ᐃG1o + ᐃG2o + ᐃG3o
- 6FEo = - 4F × 0.54 - 1F × 0.45 - 1F × 1.07
Eo = +
= + 0.61 VCreate a free account to view solution
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