ElectrochemistryHard
Question
Cu+ + e- → Cu, Eo = x1 volt ;
Cu2+ + 2e- Cu, Eo = x2 volt, then for
Cu2+ + e- Cu+, Eo (volt) will be -
Cu2+ + 2e- Cu, Eo = x2 volt, then for
Cu2+ + e- Cu+, Eo (volt) will be -
Options
A.x1 - 2x2
B.x1 + 2x2
C.x1 - x2
D.2x2 - x1
Solution
Cu+ + e- → Cu, Eo = x1 Volt
Cu2+ + 2e- → Cu , x2 Volt
Cu Cu+ + e- → - x1Volt
Cu2+ + e- → Cu+
- 2 × x2 × f + 1 × x1 × f = -1 × Eo × f
Eo = 2x2-x1
Cu2+ + 2e- → Cu , x2 Volt
Cu Cu+ + e- → - x1Volt
Cu2+ + e- → Cu+
- 2 × x2 × f + 1 × x1 × f = -1 × Eo × f
Eo = 2x2-x1
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