ElectrochemistryHard
Question
Given standard electrode potentials :
Fe3+ + 3e- → Fe ; Eo = - 0.036 volt
Fe2+ + 2e- → Fe; Eo = - 0.440 volt
The standard electrode potential Eo for Fe3+ + e- → Fe2+
Fe3+ + 3e- → Fe ; Eo = - 0.036 volt
Fe2+ + 2e- → Fe; Eo = - 0.440 volt
The standard electrode potential Eo for Fe3+ + e- → Fe2+
Options
A.-0.476 volt
B.-0.404 volt
C.0.404 volt
D.0.772 volt
Solution
Fe3+ + 3e- → Fe , - 0.036 volt
Fe → Fe2+ + 2e-, 0.44 volt
Fe3+ → + e- Fe2+
+ 3 × 0.036f - 2 × 0.44 × f = - 1 × Eo × f
Eo = 0.772 Volt
Fe → Fe2+ + 2e-, 0.44 volt
Fe3+ → + e- Fe2+
+ 3 × 0.036f - 2 × 0.44 × f = - 1 × Eo × f
Eo = 0.772 Volt
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