ElectrochemistryHard
Question
Amount of oxalic acid present in a solution can be determined by its titration with KMnO4 solution in the presence of H2SO4. The titration gives unsatisfactory result when carried out in the presence of HCl, because HCl
Options
A.gets oxidised by oxalic acid to chlorine
B.furnishes H+ ions in addition to those from oxalic acid
C.reduces permanganate to Mn2+
D.oxidises oxalic acid to carbon dioxide and water
Solution
HCl being stronger reducing agent reduces MnO4- to Mn2+ and result of the titration becomes unsatisfactory.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The oxidation states of iodine in HIO4, H3IO5 and H5IO6 are respectively...Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is 100 Ω. The con...Adding powdered Pb and Fe to a solution containing 1.0 M is each of Pb2+ and Fe2+ ions would result into the formation o...Expermentally it was found that a metal oxide has formula M0.98O. Metal M, is present as M2+and M3+ in its oxide. Fracti...Select correct statement:...