ElectrochemistryMedium
Question
Amount of oxalic acid present in a solution can be determined by its titration with KMnO4 solution in the presence of H2SO4. The titration gives unsatisfactory result when carried out in the presence of HCl, because HCl
Options
A.gets oxidised by oxalic acid to chlorine
B.furnishes H+ ions in addition to those from oxalic acid
C.reduces permanganate to Mn2+
D.oxidises oxalic acid to carbon dioxide and water
Solution
HCl being stronger reducing agent reduces MnO4- to Mn2+ and result of the titration becomes unsatisfactory.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The EMF of the cell: Zn|Zn2+ (0.01 M)||Fe2+ (0.001 M)|Fe at 298 K is 0.2905 V, then the value of equilibrium constant fo...The standard reduction potentials at 298 K for the following half reactions are given against each Zn2+(aq) + 2e ⇋...CH3O - CH = CH - NO2 ICH2 = CH - NO2 IICH2 = CH - Cl IIICH2 = CH2 IV Which of the following is the correct order of C - ...What is the standard potential of the Tl3+/Tl electrode ? if Eo Tl3+/Tl+ = 1.26 V, EoTl+/Tl+ = - 0.336 V...Oxidation state of Fe in Fe3O4 is...