Atomic StructureHard
Question
Photon having energy equivalent to the binding energy of 4th state of He+ ion is used to eject an electron from the metal with K.E. 2eV. If electron is further accelerated through the potential difference of 4V then the minimum value of de-Broglie wavelength associated with the electron is :
(h = 6.6 × 10-34 J-s, me = 9.1 × 10-31 kg, 1 eV = 1.6 × 10-19J)
(h = 6.6 × 10-34 J-s, me = 9.1 × 10-31 kg, 1 eV = 1.6 × 10-19J)
Options
A.1.1
B.5
C.9.15
D.11
Solution
Final kinetic energy of electron, KEf = 2 + 4 = 6 eV.
∴ λ =
= 5
∴ λ =
= 5Create a free account to view solution
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