Atomic StructureMedium
Question
Photon having energy equivalent to the binding energy of 4th state of He+ atom is used to eject an electron from the metal surface of work function 1.4 eV. If electrons are further accelerated through the potential difference of 4V then the minimum value of De-broglie wavelength associated with the electron is :
Options
A.1.1 (Ao)
B.5 (Ao)
C.9.15 (Ao)
D.11 (Ao)
Solution
Total energy = 
= 3.4 eV
Now K.E. = 3.4 - 1.4 = 2 eV
Now, Total energy = 2 + 4 = 6 eV i.e. potential = 6 V
For electron λ =
so λ = 5 (Ao).
= 3.4 eVNow K.E. = 3.4 - 1.4 = 2 eV
Now, Total energy = 2 + 4 = 6 eV i.e. potential = 6 V
For electron λ =
so λ = 5 (Ao).Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
A proton and a deuteron are projected towards the stationary gold nucleus in different experiments with the same speed....A radio station is emitting the radiations of frequency 2 × 104 Hz. If its frequency is doubled,...If the value of principal quantum number is 4, the possible values for magnetic quantum number will be :-...The wave function of 1s orbital of H-atom is $\Psi = \frac{1}{\sqrt{\pi}}\left( \frac{1}{a_{0}} \right)^{3/2}e^{- r/a_{0...According to Bohr′s theory, the angular momentum of an electron in 5th orbit is...