Atomic StructureHard
Question
If an electron is revolving around the nucleus of He+ ion at a distance of 4.0 Å, the magnitude of centripetal force on electron by the nucleus is (e = 1.6 × 10−19 C)
Options
A.2.88 × 10−9 N
B.2.88 × 10−7 N
C.1.152 × 10−18 N
D.1.44 × 10−9 N
Solution
$F = \frac{1}{4\pi\varepsilon_{0}}.\frac{ze^{2}}{r^{2}} = 9 \times 10^{9} \times \frac{2 \times \left( 1.6 \times 10^{- 19} \right)^{2}}{\left( 4 \times 10^{- 10} \right)^{2}} = 2.88 \times 10^{- 9}\text{ N}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Light of wavelength l falls on metal having work function hc/λ0. Photoelectric effect will take place only if :...Which is the correct order of ionic sizes ?(Atomic Number : Ce = 58, Sn = 50, Yb = 70 and Lu = 71)...Which of the following complex ions has electrons that are symmetrically filled in both t2g and eg orbitals ?...When rain is accompanied by a thunderstorm, the collected rain water will have a pH value...Some hydrogen-like atoms in ground state absorbs ‘n’ photons having same the energy and on de-excitement, it emits exact...