Atomic StructureHard
Question
For which atom or ion, the energy level of the second excited state is −13.6 eV?
Options
A.H
B.He+
C.Li2+
D.Li
Solution
$E_{n,z} = - 13.6\frac{z^{2}}{n^{2}}eV \Rightarrow - 13.6 = - 13.6 \times \frac{z^{2}}{n^{2}} \Rightarrow z = 3$
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