Solid StateHard
Question
The edge length of a face centered cubic cell of an ionic substance (NaCl) is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is
Options
A.288 pm
B.398 pm
C.618 pm
D.144 pm
Solution
For an ionic substance (NaCl) in FCC arrangement,
2(r+ + r-) = edge length
2(110 + r- ) = 508
r- = 144 pm
2(r+ + r-) = edge length
2(110 + r- ) = 508
r- = 144 pm
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