Solid StateHard
Question
The edge length of a face centered cubic cell of an ionic substance (NaCl) is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is
Options
A.288 pm
B.398 pm
C.618 pm
D.144 pm
Solution
For an ionic substance (NaCl) in FCC arrangement,
2(r+ + r-) = edge length
2(110 + r- ) = 508
r- = 144 pm
2(r+ + r-) = edge length
2(110 + r- ) = 508
r- = 144 pm
Create a free account to view solution
View Solution FreeMore Solid State Questions
The co-ordination number of fcc structure for metals is 12, since...For an Ionic solid of the general formula AB and coordination number 6, the value of the radius ratio will be...In an FCC unit cell a cube is formed by joining the centers of all the tetrahedral voids to generate a new cube.Then the...If the positions of Na+ and Cl- are interchanged in NaCl, the crystal lattice with respect to Na+ and CI- is...Glass is a...