Nuclear Physics and RadioactivityHard
Question
In hydrogen and hydrogen like atoms, the ratio of difference of energies E2n - En and E2n En varies with its atomic number z and n as -
Options
A.n2 / z2
B.z4 / n4
C.z / n
D.(n2 / z2)
Solution
En = - 
(Z2)
E2n = -
Z2 = - 
E2n - En =
E2n - En =
+ 13.6 
E2n - En =
= (10.2) 
(E2n) - (En) =
(Z2)E2n = -
Z2 = - E2n - En =
E2n - En =
+ 13.6 E2n - En =
= (10.2) (E2n) - (En) =
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