Atomic StructureMedium
Question
The highest energy state, that unexcited hydrogen atoms can reach when they are bombareded with 12.2 eV electron, is
Options
A.n = 1
B.n = 2
C.n = 3
D.n = 4
Solution
ᐃE = 13.6 
= 12.2
13.6 − 12.2 =
n2 =
⇒ n = 3
= 12.213.6 − 12.2 =
n2 =
⇒ n = 3Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
In a hydrogen atom, the electron is in nth exited state. It any com down to second exited state by emitting ten differen...The largest wavelength in the ultraviolet region of the hydrogen spectrum is 122 nm. The smallest wavelength in the infr...The radius of the orbit of an electron in a Hydrogen-like atom is 4.5 a0, where a0 is the Bohr radius. Its orbital angul...According to De Broglie, wavelength of electron in second orbit is 10-9 metre. Then the circumfrance of orbit is :-...The threshold wavelength for photoelectric emission from a material is $5200\ \text{Å}$. Photoelectrons will be emitted ...