SolutionHard
Question
The degree of dissociation (α) of a weak electrolyte, Ax By is related to van′t Hoff factor (i) by the expression :
Options
A.

B.

C.

D.

Solution
i = 1 - α + n α = 1 + α(n - 1)

Ax By → xA+y + yB-x
n = x + y
So

Ax By → xA+y + yB-x
n = x + y
So

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