Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentra

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Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations :
a .60mL $\frac{M}{10}$ HCl+ 40mL $\frac{M}{10}$ NaOH
b.55mL $\frac{M}{10}$ HCl+45mL $\frac{M}{10}$ NaOH
c.75mL $\frac{M}{5}$ HCl+ 25mL $\frac{M}{5}$ NaOH
d.100mL $\frac{M}{10}$ HCl +100mL $\frac{M}{10}$ NaOH

Accepted Answer

As N1V1 > N2V2 So acid is left at the end of reaction Nfinal solution = [H+] =N1V1-N2V2V1+V2 =15&#215;75-15&#215;2575+25 =110=0.1 pH = &ndash;log[H+] = 1

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