Hard
Question
A particle at a height ′h′ from the ground is projected with an angle 30o from the horizontal, it strikes the ground making angle 45o with horizontal. It is again projected from the same point at height h with the same speed but with an angle of 60o with horizontal. Find the angle it makes with the horizontal when it strikes the ground :
Options
A.tan-1 (4)
B.tan-1 (5)
C.tan-1 (√5)
D.tan-1 (√3)
Solution
using v = 
v =
(vertical comp. when striking)
Now tan 45o = 1
u cosθ =
u2 cos2 θ = u2 sin2 θ + 2gh .........(1)
u2
= 2gh
u2 = 4gh
u = 2
tan θ =
v =
(vertical comp. when striking)Now tan 45o = 1
u cosθ =
u2 cos2 θ = u2 sin2 θ + 2gh .........(1)
u2
= 2ghu2 = 4gh
u = 2
tan θ =
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