KinematicsHard
Question
A ball is projected from a certain point on the surface of a planet on the surface of a planet at a certain with the horizontal and vertical displacement x and y vary with time t in second as : x = 10 t ; y = - 10t - t2 the maximum height attained by the ball is
Options
A.100 m
B.75 m
C.50 m
D.250 m
Solution
x = 10√3t ; y = 10t - t2 ; 
= 10√3
vy =
= 10 - 2t at ⇒ t = 5 sec
vy becomes zero at maximum height
⇒ y = 10 × 5 - 52 - 25m.
= 10√3vy =
= 10 - 2t at ⇒ t = 5 sec vy becomes zero at maximum height
⇒ y = 10 × 5 - 52 - 25m.
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