Atomic StructureHard

Question

A electron in the hydrogen atom jumped from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, then the value of n is

Options

A.2
B.3
C.4
D.5

Solution

Here, stopping potential, V0 = 10V
Work function, W = 2.75 eV
According to Einstein′s photoelectric equation
       
or      
      = 10 eV + 2.75 eV = 12.75 eV    ...... (i)
When an electron in the hydrogen atom makes a transition from excited state n to the ground state (n = 1), then he frequency ( ) of the emitted photon is given by
     h = En - E1
     h = -
                [∵ For hydrogen atom, En = ]
According to the given problem
      + 13.6 = 12.75         [Using (i)]
      = 0.85       ⇒ n2 =
or n = 4

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