Chemical EquilibriumHard
Question
In a reaction carried out at 500 K, 0.001% of the total number of collisions are effective. The energy of activation of the reaction is approximately
Options
A.15.8 kcal mol-1
B.11.5 kcal mol-1
C.12.8 kcal mol-1
D.zero
Solution
The fraction of molecules having energy equal to or greater than Ea is:
x =
= e -Ea/RT 
∴ log x =
(R = 2 cal mol-1 K-1, T = 500K)
log 10-5 =
Ea = 11.5 × 103 cal mol-1 = 11.5 kcal mol-1
x =
= e -Ea/RT ∴ log x =
(R = 2 cal mol-1 K-1, T = 500K)log 10-5 =
Ea = 11.5 × 103 cal mol-1 = 11.5 kcal mol-1
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