Mole ConceptHard
Question
In Duma′s method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound will be (Aqueous tension at 300 K = 15 mm)
Options
A.16.45
B.17.45
C.14.45
D.15.45
Solution
Where, P2 = pressure of N2 at STP = 760 mm
T2 = Temperature of N2 at STP = 273 K
V2 = ?
Volume of N 2 at STP (By gas equation)
Where, P1 = ρ - ρ1
ρ = 715 mm (pressure at which N2 collected).
ρ1 = aqueous tension of water = 15 mm
T1 = t + 273 = 300 K
V1 = 55 mL = volume of moist nitrogen in nitrometer
∴
= 46.098 mL% of nitrogen in given compound =
100 = 16.45% Create a free account to view solution
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