Mole ConceptHard
Question
A volume of 10 ml of gaseous C4Hx exactly requires 55 ml O2 for complete combustion. The value of ‘x’ is
Options
A.4
B.6
C.8
D.10
Solution
$C_{4}H_{x} + \left( 4 + \frac{x}{4} \right)O_{2} \rightarrow 4CO_{2} + \frac{x}{2}H_{2}O$
$10\text{ mL} \text{10}\left( 4 + \frac{x}{4} \right) = 55 \Rightarrow x = 6$
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