ElectrochemistryHard
Question
The elctrode potentials for
Cu2+ (aq) + e- → Cu+(aq)
and Cu+ (aq) + e- → Cu (s)
are +0.15 V and +0.50 V respectively. The value of EoCu2+/Cu will be
Cu2+ (aq) + e- → Cu+(aq)
and Cu+ (aq) + e- → Cu (s)
are +0.15 V and +0.50 V respectively. The value of EoCu2+/Cu will be
Options
A.0.325 V
B.0.650 V
C.0.150 V
D.0.500 V
Solution
Cu2+ + e- → Cu+
Eo1 = 0.15 V; ᐃGo1 = - n1Eo1F
Cu+ + e- → Cu; Eo2 = 0.50 V; ᐃGo2 = - n2Eo2F
Cu+ + e- → Cu ; Eo = ?; ᐃGo = - nEoF
ᐃGo = ᐃGo1 + ᐃGoo
or - 2EoF = - 2F × 0. 15 + ( - 1F × 0.15)
or - 2EoF = - 0.15F - 0.50F
or - 2 FEo = - F ( 0.15 + 0.50 )
∴ Eo =
= 0.325 V
Eo1 = 0.15 V; ᐃGo1 = - n1Eo1F
Cu+ + e- → Cu; Eo2 = 0.50 V; ᐃGo2 = - n2Eo2F
Cu+ + e- → Cu ; Eo = ?; ᐃGo = - nEoF
ᐃGo = ᐃGo1 + ᐃGoo
or - 2EoF = - 2F × 0. 15 + ( - 1F × 0.15)
or - 2EoF = - 0.15F - 0.50F
or - 2 FEo = - F ( 0.15 + 0.50 )
∴ Eo =
= 0.325 VCreate a free account to view solution
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