Chemical EquilibriumMedium

Question

For the reaction $2A \rightleftharpoons B + C,K_{C} = 4 \times 10^{- 3}$. At a given time, the composition of reaction mixture is:

$\lbrack A\rbrack = \lbrack B\rbrack = \lbrack C\rbrack = 2 \times 10^{- 3}M$.

Then, which of the following is correct?

Options

A.Reaction has a tendency to go in backward direction.
B.Reaction has gone to completion in forward direction.
C.Reaction is at equilibrium.
D.Reaction has a tendency to go in forward direction.

Solution

Sol. [Key Concept: Reaction quotient and direction of reaction]

$$2\text{ }A \rightleftharpoons \text{ }B + C,K_{C} = 4 \times 10^{- 3} $$At a given time $t_{1}Q_{c}$ is to be calculated and been compared with $K_{c}$.

$$\begin{matrix} & Q_{C} = \frac{\lbrack B\rbrack\lbrack C\rbrack}{\lbrack A\rbrack^{2}} = \frac{\left( 2 \times 10^{- 3} \right)\left( 2 \times 10^{- 3} \right)}{\left( 2 \times 10^{- 3} \right)^{2}} \\ & Q_{C} = 1 \end{matrix}$$

As $Q_{c} > K_{c}$, so reaction has a tendency to move backward.

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions