Chemical EquilibriumHard
Question
For given two equilibrium attained in a container which are correct if degree of dissociation of A and A′ are α and α′.
A(s) ⇋ 2B(g) + C(g); Kp1 = 8 × 10-2
A′(s) ⇋ 2B + D(g); Kp2 = 2 × 10-2
A(s) ⇋ 2B(g) + C(g); Kp1 = 8 × 10-2
A′(s) ⇋ 2B + D(g); Kp2 = 2 × 10-2
Options
A.
B.P′C/P′D = 4
C.P′B = 2P′C + 2P′D
D.α > α′
Solution
A(s) 2B(g) + C(s)
2α + 2α′ α
Aα(s) 2B + D
2α + 2α α′
Kp1 = (2α + 2α′) × α ×
Kp2 = (2α + 2α′) ×α′ ×

Also, KP1 = (P′B)2 × P′C
KP2 = (P′B)2 × P′p
or
Also, P′B = 2 × (P′C + P′D)
KP1 > KP2 ∴ α > α1
2α + 2α′ α
Aα(s) 2B + D
2α + 2α α′
Kp1 = (2α + 2α′) × α ×
Kp2 = (2α + 2α′) ×α′ ×
Also, KP1 = (P′B)2 × P′C
KP2 = (P′B)2 × P′p
or
Also, P′B = 2 × (P′C + P′D)
KP1 > KP2 ∴ α > α1
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