Chemical EquilibriumHard
Question
A 10 litre box contains O3 and O2 at equilibrium at 2000 K. KP = 4 × 1014 atm for 2O3 (g) ⇋ 3O2(g). Assume that PO2 > > PO3 and if total pressure is 8 atm, then partial pressure of O3 will be :
Options
A.8 × 10-5 atm
B.11.3 × 10-7 atm
C.9.71 × 10-6 atm
D.9.71 × 10-2 atm
Solution
2O3(g) ⇋ 3O2(g) Kp = 4 × 1014 pO2 > > pO3
Kp =
pO2 + PO3 = 8 ⇒ PO2 ≃ 8 atm.
4 × 1014 =
p2O3 = 11.3 × 10-7
Kp =
pO2 + PO3 = 8 ⇒ PO2 ≃ 8 atm.4 × 1014 =
p2O3 = 11.3 × 10-7Create a free account to view solution
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